13311311210000 has 100 divisors (see below), whose sum is σ = 32250446553600. Its totient is φ = 5320818576000.

The previous prime is 13311311209997. The next prime is 13311311210059. The reversal of 13311311210000 is 1211311331.

13311311210000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (100).

It is a super-2 number, since 2×13311311210000² (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 13927481 + ... + 14852519.

It is an arithmetic number, because the mean of its divisors is an integer number (322504465536).

Almost surely, 2^{13311311210000} is an apocalyptic number.

13311311210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311311210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16125223276800).

13311311210000 is an abundant number, since it is smaller than the sum of its proper divisors (18939135343600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311311210000 is an equidigital number, since it uses as much as digits as its factorization.

13311311210000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 926506 (or 926485 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13311311210000 its reverse (1211311331), we get a palindrome (13312522521331).

The spelling of 13311311210000 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, two hundred ten thousand".