Base | Representation |
---|---|
bin | 1100000110111011010001… |
… | …1101001110111000001100 |
3 | 1202010201112000010020220220 |
4 | 3001232310131032320030 |
5 | 3221110243042243200 |
6 | 44151545033111340 |
7 | 2542561542111603 |
oct | 301566435167014 |
9 | 52121460106826 |
10 | 13313131212300 |
11 | 4273081551167 |
12 | 15b0210858550 |
13 | 75756610a21a |
14 | 3405050caa3a |
15 | 181489a654a0 |
hex | c1bb474ee0c |
13313131212300 has 72 divisors (see below), whose sum is σ = 39338886483456. Its totient is φ = 3474632823360.
The previous prime is 13313131212263. The next prime is 13313131212301. The reversal of 13313131212300 is 321213131331.
13313131212300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13313131212301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 472082752 + ... + 472110951.
Almost surely, 213313131212300 is an apocalyptic number.
13313131212300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13313131212300 is an abundant number, since it is smaller than the sum of its proper divisors (26025755271156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13313131212300 is a wasteful number, since it uses less digits than its factorization.
13313131212300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 944193767 (or 944193760 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 13313131212300 its reverse (321213131331), we get a palindrome (13634344343631).
The spelling of 13313131212300 in words is "thirteen trillion, three hundred thirteen billion, one hundred thirty-one million, two hundred twelve thousand, three hundred".
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