Base | Representation |
---|---|
bin | 10011011000101001010… |
… | …000010110000100001100 |
3 | 11201100110120101210122210 |
4 | 103120221100112010030 |
5 | 133311201243343200 |
6 | 2455550100110420 |
7 | 165146321163465 |
oct | 23305120260414 |
9 | 4640416353583 |
10 | 1332132012300 |
11 | 473a54879661 |
12 | 196214395410 |
13 | 988090a827b |
14 | 48692c13d6c |
15 | 249b9cdb650 |
hex | 1362941610c |
1332132012300 has 72 divisors (see below), whose sum is σ = 3958472311696. Its totient is φ = 345634248960.
The previous prime is 1332132012293. The next prime is 1332132012313. The reversal of 1332132012300 is 32102312331.
It is a super-3 number, since 3×13321320123003 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 59994847 + ... + 60017046.
Almost surely, 21332132012300 is an apocalyptic number.
1332132012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1332132012300 is an abundant number, since it is smaller than the sum of its proper divisors (2626340299396).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1332132012300 is a wasteful number, since it uses less digits than its factorization.
1332132012300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120011947 (or 120011940 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1332132012300 its reverse (32102312331), we get a palindrome (1364234324631).
The spelling of 1332132012300 in words is "one trillion, three hundred thirty-two billion, one hundred thirty-two million, twelve thousand, three hundred".
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