| Base | Representation |
|---|---|
| bin | 11000110101000011… |
| … | …00111110010110010 |
| 3 | 1021101222121021002010 |
| 4 | 30122201213302302 |
| 5 | 204244430021000 |
| 6 | 10042414303350 |
| 7 | 651220323000 |
| oct | 143241476262 |
| 9 | 37358537063 |
| 10 | 13329923250 |
| 11 | 57204376a6 |
| 12 | 27001b7b56 |
| 13 | 1345848867 |
| 14 | 9064cba70 |
| 15 | 5303c1d50 |
| hex | 31a867cb2 |
13329923250 has 128 divisors (see below), whose sum is σ = 38801318400. Its totient is φ = 3046780800.
The previous prime is 13329923249. The next prime is 13329923251. The reversal of 13329923250 is 5232992331.
13329923250 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13329923249) and next prime (13329923251).
It is a hoax number, since the sum of its digits (39) coincides with the sum of the digits of its distinct prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 13329923199 and 13329923208.
It is not an unprimeable number, because it can be changed into a prime (13329923251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 231342 + ... + 283158.
It is an arithmetic number, because the mean of its divisors is an integer number (303135300).
Almost surely, 213329923250 is an apocalyptic number.
13329923250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13329923250, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19400659200).
13329923250 is an abundant number, since it is smaller than the sum of its proper divisors (25471395150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13329923250 is an equidigital number, since it uses as much as digits as its factorization.
13329923250 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51858 (or 51834 counting only the distinct ones).
The product of its (nonzero) digits is 87480, while the sum is 39.
The spelling of 13329923250 in words is "thirteen billion, three hundred twenty-nine million, nine hundred twenty-three thousand, two hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •