13332101114020 has 24 divisors (see below), whose sum is σ = 30151059443064. Its totient is φ = 4922621949696.

The previous prime is 13332101114011. The next prime is 13332101114021. The reversal of 13332101114020 is 2041110123331.

It can be written as a sum of positive squares in 4 ways, for example, as 2059644041316 + 11272457072704 = 1435146^2 + 3357448^2 .

It is a super-2 number, since 2×13332101114020² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13332101113982 and 13332101114000.

It is not an unprimeable number, because it can be changed into a prime (13332101114021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25638655729 + ... + 25638656248.

It is an arithmetic number, because the mean of its divisors is an integer number (1256294143461).

Almost surely, 2^{13332101114020} is an apocalyptic number.

13332101114020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13332101114020 is an abundant number, since it is smaller than the sum of its proper divisors (16818958329044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13332101114020 is a wasteful number, since it uses less digits than its factorization.

13332101114020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51277311999 (or 51277311997 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13332101114020 its reverse (2041110123331), we get a palindrome (15373211237351).

The spelling of 13332101114020 in words is "thirteen trillion, three hundred thirty-two billion, one hundred one million, one hundred fourteen thousand, twenty".