Base | Representation |
---|---|
bin | 11110010100001110011000… |
… | …000100100101110011110000 |
3 | 122111002100012001020022100110 |
4 | 132110032120010211303300 |
5 | 114433444320101010000 |
6 | 1151323303431221320 |
7 | 40040601645016434 |
oct | 3624163004456360 |
9 | 574070161208313 |
10 | 133331221110000 |
11 | 395354a9419251 |
12 | 12b54598217840 |
13 | 5952107281974 |
14 | 24cd3a08a89c4 |
15 | 10633b73d0850 |
hex | 794398125cf0 |
133331221110000 has 400 divisors, whose sum is σ = 454299387660800. Its totient is φ = 33591843072000.
The previous prime is 133331221109993. The next prime is 133331221110001. The reversal of 133331221110000 is 11122133331.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (400).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133331221110001) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 208871316 + ... + 209508684.
It is an arithmetic number, because the mean of its divisors is an integer number (1135748469152).
Almost surely, 2133331221110000 is an apocalyptic number.
133331221110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133331221110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (227149693830400).
133331221110000 is an abundant number, since it is smaller than the sum of its proper divisors (320968166550800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133331221110000 is a wasteful number, since it uses less digits than its factorization.
133331221110000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 637786 (or 637765 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 133331221110000 its reverse (11122133331), we get a palindrome (133342343243331).
The spelling of 133331221110000 in words is "one hundred thirty-three trillion, three hundred thirty-one billion, two hundred twenty-one million, one hundred ten thousand".
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