Base | Representation |
---|---|
bin | 11110010101001011010011… |
… | …011100011010100001000000 |
3 | 122111022121001022122122122020 |
4 | 132111023103130122201000 |
5 | 114441032310240023014 |
6 | 1151413323214041440 |
7 | 40045406065024110 |
oct | 3625132334324100 |
9 | 574277038578566 |
10 | 133396641720384 |
11 | 3956021a6760a9 |
12 | 12b651b54a9280 |
13 | 5958331a47203 |
14 | 24d260922b040 |
15 | 1064e459701a9 |
hex | 7952d371a840 |
133396641720384 has 112 divisors (see below), whose sum is σ = 403498342608000. Its totient is φ = 38100824764416.
The previous prime is 133396641720359. The next prime is 133396641720403. The reversal of 133396641720384 is 483027146693331.
It is a tau number, because it is divible by the number of its divisors (112).
It is a super-2 number, since 2×1333966417203842 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12178539 + ... + 20374250.
Almost surely, 2133396641720384 is an apocalyptic number.
133396641720384 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
133396641720384 is an abundant number, since it is smaller than the sum of its proper divisors (270101700887616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133396641720384 is a wasteful number, since it uses less digits than its factorization.
133396641720384 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32555860 (or 32555850 counting only the distinct ones).
The product of its (nonzero) digits is 47029248, while the sum is 60.
The spelling of 133396641720384 in words is "one hundred thirty-three trillion, three hundred ninety-six billion, six hundred forty-one million, seven hundred twenty thousand, three hundred eighty-four".
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