Base | Representation |
---|---|
bin | 11000110110010100… |
… | …01011011101011111 |
3 | 1021102201121102020110 |
4 | 30123022023131133 |
5 | 204310140230403 |
6 | 10043434221103 |
7 | 651406563441 |
oct | 143312133537 |
9 | 37381542213 |
10 | 13340555103 |
11 | 5726439557 |
12 | 2703884793 |
13 | 1347acbbb5 |
14 | 907a98491 |
15 | 5312c2103 |
hex | 31b28b75f |
13340555103 has 4 divisors (see below), whose sum is σ = 17787406808. Its totient is φ = 8893703400.
The previous prime is 13340555099. The next prime is 13340555117. The reversal of 13340555103 is 30155504331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30155504331 = 3 ⋅10051834777.
It is not a de Polignac number, because 13340555103 - 22 = 13340555099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13340550103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223425848 + ... + 2223425853.
It is an arithmetic number, because the mean of its divisors is an integer number (4446851702).
Almost surely, 213340555103 is an apocalyptic number.
13340555103 is a deficient number, since it is larger than the sum of its proper divisors (4446851705).
13340555103 is an equidigital number, since it uses as much as digits as its factorization.
13340555103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4446851704.
The product of its (nonzero) digits is 13500, while the sum is 30.
The spelling of 13340555103 in words is "thirteen billion, three hundred forty million, five hundred fifty-five thousand, one hundred three".
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