1334110453 has 4 divisors (see below), whose sum is σ = 1436734348. Its totient is φ = 1231486560.

The previous prime is 1334110429. The next prime is 1334110457. The reversal of 1334110453 is 3540114331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3540114331 = 13 ⋅272316487.

It can be written as a sum of positive squares in 2 ways, for example, as 636199729 + 697910724 = 25223^2 + 26418^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1334110453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1334110457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51311928 + ... + 51311953.

It is an arithmetic number, because the mean of its divisors is an integer number (359183587).

Almost surely, 2^1334110453 is an apocalyptic number.

1334110453 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1334110453 is a deficient number, since it is larger than the sum of its proper divisors (102623895).

1334110453 is a wasteful number, since it uses less digits than its factorization.

1334110453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102623894.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 1334110453 is about 36525.4767662244. The cubic root of 1334110453 is about 1100.8562074852.

Adding to 1334110453 its reverse (3540114331), we get a palindrome (4874224784).

The spelling of 1334110453 in words is "one billion, three hundred thirty-four million, one hundred ten thousand, four hundred fifty-three".