Base | Representation |
---|---|
bin | 111110001000000000… |
… | …0000101001111011110 |
3 | 110202100202001022112101 |
4 | 1330100000011033132 |
5 | 4141212041134402 |
6 | 141142215355314 |
7 | 12432041025031 |
oct | 1742000051736 |
9 | 422322038471 |
10 | 133412443102 |
11 | 51641934144 |
12 | 21a33682b3a |
13 | c771b66233 |
14 | 6658795018 |
15 | 370c727b87 |
hex | 1f100053de |
133412443102 has 4 divisors (see below), whose sum is σ = 200118664656. Its totient is φ = 66706221550.
The previous prime is 133412443097. The next prime is 133412443103. The reversal of 133412443102 is 201344214331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133412443103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33353110774 + ... + 33353110777.
It is an arithmetic number, because the mean of its divisors is an integer number (50029666164).
Almost surely, 2133412443102 is an apocalyptic number.
133412443102 is a deficient number, since it is larger than the sum of its proper divisors (66706221554).
133412443102 is an equidigital number, since it uses as much as digits as its factorization.
133412443102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66706221553.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 133412443102 its reverse (201344214331), we get a palindrome (334756657433).
The spelling of 133412443102 in words is "one hundred thirty-three billion, four hundred twelve million, four hundred forty-three thousand, one hundred two".
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