Base | Representation |
---|---|
bin | 1100001000101010100011… |
… | …1101000110100001000100 |
3 | 1202020120121211011212100220 |
4 | 3002022220331012201010 |
5 | 3222102432232324030 |
6 | 44213405125304340 |
7 | 2545000024161255 |
oct | 302125075064104 |
9 | 52216554155326 |
10 | 13343003011140 |
11 | 4284810391820 |
12 | 15b5b688650b0 |
13 | 75a316a6653a |
14 | 341b3a4c2b2c |
15 | 1821372b8a10 |
hex | c22a8f46844 |
13343003011140 has 48 divisors (see below), whose sum is σ = 40756809199680. Its totient is φ = 3234667396480.
The previous prime is 13343003011127. The next prime is 13343003011193. The reversal of 13343003011140 is 4111030034331.
It is a super-3 number, since 3×133430030111403 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 13343003011140.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10108334955 + ... + 10108336274.
It is an arithmetic number, because the mean of its divisors is an integer number (849100191660).
Almost surely, 213343003011140 is an apocalyptic number.
13343003011140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13343003011140 is an abundant number, since it is smaller than the sum of its proper divisors (27413806188540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13343003011140 is a wasteful number, since it uses less digits than its factorization.
13343003011140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20216671252 (or 20216671250 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13343003011140 its reverse (4111030034331), we get a palindrome (17454033045471).
The spelling of 13343003011140 in words is "thirteen trillion, three hundred forty-three billion, three million, eleven thousand, one hundred forty".
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