Base | Representation |
---|---|
bin | 11110010101110101111100… |
… | …110101001111101111111001 |
3 | 122111110222020121111111102110 |
4 | 132111311330311033233321 |
5 | 114442310100403033340 |
6 | 1151450335121322533 |
7 | 40051616615436540 |
oct | 3625657465175771 |
9 | 574428217444373 |
10 | 133442433252345 |
11 | 39578688808898 |
12 | 12b72054a96449 |
13 | 595c74b934a59 |
14 | 24d4910a5d157 |
15 | 1066225b11680 |
hex | 795d7cd4fbf9 |
133442433252345 has 64 divisors (see below), whose sum is σ = 254793593032704. Its totient is φ = 58309768070400.
The previous prime is 133442433252311. The next prime is 133442433252419. The reversal of 133442433252345 is 543252334244331.
It is not a de Polignac number, because 133442433252345 - 211 = 133442433250297 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 133442433252294 and 133442433252303.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15536382 + ... + 22544711.
It is an arithmetic number, because the mean of its divisors is an integer number (3981149891136).
Almost surely, 2133442433252345 is an apocalyptic number.
133442433252345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133442433252345 is a deficient number, since it is larger than the sum of its proper divisors (121351159780359).
133442433252345 is a wasteful number, since it uses less digits than its factorization.
133442433252345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38082582.
The product of its digits is 12441600, while the sum is 48.
Adding to 133442433252345 its reverse (543252334244331), we get a palindrome (676694767496676).
The spelling of 133442433252345 in words is "one hundred thirty-three trillion, four hundred forty-two billion, four hundred thirty-three million, two hundred fifty-two thousand, three hundred forty-five".
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