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1334814949253 is a prime number
BaseRepresentation
bin10011011011001001001…
…010111011111110000101
311201121101112211010021002
4103123021022323332011
5133332200111334003
62501112220503045
7165302646602222
oct23331112737605
94647345733232
101334814949253
11475101270925
121968429aaa85
1398b45b99326
1448869284949
1524ac5600a88
hex136c92bbf85

1334814949253 has 2 divisors, whose sum is σ = 1334814949254. Its totient is φ = 1334814949252.

The previous prime is 1334814949241. The next prime is 1334814949451. The reversal of 1334814949253 is 3529494184331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1100889888289 + 233925060964 = 1049233^2 + 483658^2 .

It is an emirp because it is prime and its reverse (3529494184331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1334814949253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1334814949453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667407474626 + 667407474627.

It is an arithmetic number, because the mean of its divisors is an integer number (667407474627).

Almost surely, 21334814949253 is an apocalyptic number.

It is an amenable number.

1334814949253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334814949253 is an equidigital number, since it uses as much as digits as its factorization.

1334814949253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11197440, while the sum is 56.

The spelling of 1334814949253 in words is "one trillion, three hundred thirty-four billion, eight hundred fourteen million, nine hundred forty-nine thousand, two hundred fifty-three".