Base | Representation |
---|---|
bin | 111110001011111001… |
… | …0101100000111100111 |
3 | 110202200211222220202122 |
4 | 1330113302230013213 |
5 | 4141444021300210 |
6 | 141203205100155 |
7 | 12435216021620 |
oct | 1742762540747 |
9 | 422624886678 |
10 | 133543150055 |
11 | 516a9699217 |
12 | 21a6b3b765b |
13 | c792c6b723 |
14 | 666bc9aa47 |
15 | 3718e45b55 |
hex | 1f17cac1e7 |
133543150055 has 64 divisors (see below), whose sum is σ = 204291072000. Its totient is φ = 81583054848.
The previous prime is 133543150009. The next prime is 133543150067. The reversal of 133543150055 is 550051345331.
It is not a de Polignac number, because 133543150055 - 28 = 133543149799 is a prime.
It is a super-2 number, since 2×1335431500552 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a junction number, because it is equal to n+sod(n) for n = 133543149997 and 133543150024.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 16263791 + ... + 16271999.
It is an arithmetic number, because the mean of its divisors is an integer number (3192048000).
Almost surely, 2133543150055 is an apocalyptic number.
133543150055 is a deficient number, since it is larger than the sum of its proper divisors (70747921945).
133543150055 is a wasteful number, since it uses less digits than its factorization.
133543150055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9696.
The product of its (nonzero) digits is 67500, while the sum is 35.
Adding to 133543150055 its reverse (550051345331), we get a palindrome (683594495386).
The spelling of 133543150055 in words is "one hundred thirty-three billion, five hundred forty-three million, one hundred fifty thousand, fifty-five".
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