Base | Representation |
---|---|
bin | 11110011101111101101100… |
… | …110111011101010110111000 |
3 | 122120110022202000111212101002 |
4 | 132131331230313131112320 |
5 | 120030431021323123100 |
6 | 1152554552431344132 |
7 | 40140134404321454 |
oct | 3635755467352670 |
9 | 576408660455332 |
10 | 134000511145400 |
11 | 39773330178a09 |
12 | 13042244082048 |
13 | 59a026a238a03 |
14 | 2513933355664 |
15 | 10759da36e2d5 |
hex | 79df6cddd5b8 |
134000511145400 has 96 divisors (see below), whose sum is σ = 312656604812640. Its totient is φ = 53410158005760.
The previous prime is 134000511145393. The next prime is 134000511145493. The reversal of 134000511145400 is 4541115000431.
134000511145400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1340005111454002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 161700509 + ... + 162527091.
It is an arithmetic number, because the mean of its divisors is an integer number (3256839633465).
Almost surely, 2134000511145400 is an apocalyptic number.
134000511145400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134000511145400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156328302406320).
134000511145400 is an abundant number, since it is smaller than the sum of its proper divisors (178656093667240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134000511145400 is a wasteful number, since it uses less digits than its factorization.
134000511145400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 829473 (or 829464 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 134000511145400 its reverse (4541115000431), we get a palindrome (138541626145831).
The spelling of 134000511145400 in words is "one hundred thirty-four trillion, five hundred eleven million, one hundred forty-five thousand, four hundred".
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