Base | Representation |
---|---|
bin | 1100001100000010101100… |
… | …0100000010001011010100 |
3 | 1202110010101011012200120112 |
4 | 3003000223010002023110 |
5 | 3224030242213110200 |
6 | 44300202132222152 |
7 | 2552122531201052 |
oct | 303005304021324 |
9 | 52403334180515 |
10 | 13401020441300 |
11 | 42a7382747808 |
12 | 160525a76a958 |
13 | 76293183cb7b |
14 | 3448819371d2 |
15 | 1838d094d535 |
hex | c302b1022d4 |
13401020441300 has 36 divisors (see below), whose sum is σ = 29092584163776. Its totient is φ = 5358128028000.
The previous prime is 13401020441299. The next prime is 13401020441323. The reversal of 13401020441300 is 314402010431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 28265582 + ... + 28735781.
Almost surely, 213401020441300 is an apocalyptic number.
13401020441300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13401020441300 is an abundant number, since it is smaller than the sum of its proper divisors (15691563722476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401020441300 is a wasteful number, since it uses less digits than its factorization.
13401020441300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57003728 (or 57003721 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13401020441300 its reverse (314402010431), we get a palindrome (13715422451731).
The spelling of 13401020441300 in words is "thirteen trillion, four hundred one billion, twenty million, four hundred forty-one thousand, three hundred".
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