Base | Representation |
---|---|
bin | 11000111101100001… |
… | …10101101100010000 |
3 | 1021120221101102010112 |
4 | 30132300311230100 |
5 | 204421130134300 |
6 | 10053434220452 |
7 | 653042541440 |
oct | 143660655420 |
9 | 37527342115 |
10 | 13401021200 |
11 | 5757588636 |
12 | 271bb84728 |
13 | 13574b0058 |
14 | 911b18120 |
15 | 536767e35 |
hex | 31ec35b10 |
13401021200 has 60 divisors (see below), whose sum is σ = 36795383040. Its totient is φ = 4594634880.
The previous prime is 13401021187. The next prime is 13401021203. The reversal of 13401021200 is 212010431.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is not an unprimeable number, because it can be changed into a prime (13401021203) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2390240 + ... + 2395839.
It is an arithmetic number, because the mean of its divisors is an integer number (613256384).
Almost surely, 213401021200 is an apocalyptic number.
13401021200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13401021200 is an abundant number, since it is smaller than the sum of its proper divisors (23394361840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401021200 is a wasteful number, since it uses less digits than its factorization.
13401021200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4786104 (or 4786093 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 13401021200 its reverse (212010431), we get a palindrome (13613031631).
The spelling of 13401021200 in words is "thirteen billion, four hundred one million, twenty-one thousand, two hundred".
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