13401141303 has 8 divisors (see below), whose sum is σ = 19492569216. Its totient is φ = 8121903800.

The previous prime is 13401141283. The next prime is 13401141343. The reversal of 13401141303 is 30314110431.

13401141303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13401141303 - 2¹⁶ = 13401075767 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13401141303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401141343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 203047563 + ... + 203047628.

It is an arithmetic number, because the mean of its divisors is an integer number (2436571152).

Almost surely, 2^13401141303 is an apocalyptic number.

13401141303 is a deficient number, since it is larger than the sum of its proper divisors (6091427913).

13401141303 is a wasteful number, since it uses less digits than its factorization.

13401141303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 406095205.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13401141303 its reverse (30314110431), we get a palindrome (43715251734).

The spelling of 13401141303 in words is "thirteen billion, four hundred one million, one hundred forty-one thousand, three hundred three".