Base | Representation |
---|---|
bin | 10011100000000101011… |
… | …101000111000010010000 |
3 | 11202010002100200100110102 |
4 | 103200011131013002100 |
5 | 133424032024012144 |
6 | 2503350534351532 |
7 | 165551312133545 |
oct | 23400535070220 |
9 | 4663070610412 |
10 | 1340121313424 |
11 | 4773845a9863 |
12 | 197883abb5a8 |
13 | 994b034369a |
14 | 48c0dcd4bcc |
15 | 24cd63c1b4e |
hex | 13805747090 |
1340121313424 has 10 divisors (see below), whose sum is σ = 2596485044790. Its totient is φ = 670060656704.
The previous prime is 1340121313423. The next prime is 1340121313469. The reversal of 1340121313424 is 4243131210431.
It can be written as a sum of positive squares in only one way, i.e., 1255072090000 + 85049223424 = 1120300^2 + 291632^2 .
It is not an unprimeable number, because it can be changed into a prime (1340121313423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41878791029 + ... + 41878791060.
It is an arithmetic number, because the mean of its divisors is an integer number (259648504479).
Almost surely, 21340121313424 is an apocalyptic number.
It is an amenable number.
1340121313424 is a deficient number, since it is larger than the sum of its proper divisors (1256363731366).
1340121313424 is an equidigital number, since it uses as much as digits as its factorization.
1340121313424 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83757582097 (or 83757582091 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1340121313424 its reverse (4243131210431), we get a palindrome (5583252523855).
The spelling of 1340121313424 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, three hundred thirteen thousand, four hundred twenty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •