1340121313425 has 12 divisors (see below), whose sum is σ = 2215667238320. Its totient is φ = 714731367120.

The previous prime is 1340121313423. The next prime is 1340121313469. The reversal of 1340121313425 is 5243131210431.

It is not a de Polignac number, because 1340121313425 - 2¹ = 1340121313423 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340121313392 and 1340121313401.

It is not an unprimeable number, because it can be changed into a prime (1340121313423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8934142015 + ... + 8934142164.

Almost surely, 2^{1340121313425} is an apocalyptic number.

1340121313425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1340121313425 is a deficient number, since it is larger than the sum of its proper divisors (875545924895).

1340121313425 is a wasteful number, since it uses less digits than its factorization.

1340121313425 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17868284192 (or 17868284187 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 1340121313425 its reverse (5243131210431), we get a palindrome (6583252523856).

The spelling of 1340121313425 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, three hundred thirteen thousand, four hundred twenty-five".