Base | Representation |
---|---|
bin | 11000111101100011… |
… | …01011111010111000 |
3 | 1021120221210200211012 |
4 | 30132301223322320 |
5 | 204421204241240 |
6 | 10053443053052 |
7 | 653044455143 |
oct | 143661537270 |
9 | 37527720735 |
10 | 13401243320 |
11 | 575771a503 |
12 | 2720071188 |
13 | 135755a19a |
14 | 911b7505a |
15 | 5367adb65 |
hex | 31ec6beb8 |
13401243320 has 32 divisors (see below), whose sum is σ = 30164155920. Its totient is φ = 5358478080.
The previous prime is 13401243311. The next prime is 13401243347. The reversal of 13401243320 is 2334210431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46775 + ... + 170265.
Almost surely, 213401243320 is an apocalyptic number.
13401243320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13401243320 is an abundant number, since it is smaller than the sum of its proper divisors (16762912600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401243320 is a wasteful number, since it uses less digits than its factorization.
13401243320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126215 (or 126211 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13401243320 its reverse (2334210431), we get a palindrome (15735453751).
The spelling of 13401243320 in words is "thirteen billion, four hundred one million, two hundred forty-three thousand, three hundred twenty".
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