134013121433020 has 144 divisors (see below), whose sum is σ = 294379752034368. Its totient is φ = 51239776573440.

The previous prime is 134013121433017. The next prime is 134013121433041. The reversal of 134013121433020 is 20334121310431.

It is a self number, because there is not a number n which added to its sum of digits gives 134013121433020.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7659196912 + ... + 7659214408.

It is an arithmetic number, because the mean of its divisors is an integer number (2044303833572).

Almost surely, 2^{134013121433020} is an apocalyptic number.

134013121433020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134013121433020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147189876017184).

134013121433020 is an abundant number, since it is smaller than the sum of its proper divisors (160366630601348).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134013121433020 is a wasteful number, since it uses less digits than its factorization.

134013121433020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22088 (or 22057 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 134013121433020 its reverse (20334121310431), we get a palindrome (154347242743451).

The spelling of 134013121433020 in words is "one hundred thirty-four trillion, thirteen billion, one hundred twenty-one million, four hundred thirty-three thousand, twenty".