13401430042000 has 320 divisors, whose sum is σ = 43508358286848. Its totient is φ = 3855755520000.

The previous prime is 13401430041949. The next prime is 13401430042001. The reversal of 13401430042000 is 24003410431.

It is a super-3 number, since 3×13401430042000³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is not an unprimeable number, because it can be changed into a prime (13401430042001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1345011 + ... + 5349010.

Almost surely, 2^{13401430042000} is an apocalyptic number.

13401430042000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13401430042000 is an abundant number, since it is smaller than the sum of its proper divisors (30106928244848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401430042000 is a wasteful number, since it uses less digits than its factorization.

13401430042000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6694075 (or 6694059 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13401430042000 its reverse (24003410431), we get a palindrome (13425433452431).

The spelling of 13401430042000 in words is "thirteen trillion, four hundred one billion, four hundred thirty million, forty-two thousand".