Base | Representation |
---|---|
bin | 1100001100000111100000… |
… | …0100101000010101000000 |
3 | 1202110020201012100011222202 |
4 | 3003001320010220111000 |
5 | 3224040413441140300 |
6 | 44300534244252332 |
7 | 2552166540060332 |
oct | 303017004502500 |
9 | 52406635304882 |
10 | 13402312443200 |
11 | 42a7985a8197a |
12 | 160555b3a10a8 |
13 | 762aa9407535 |
14 | 344965375452 |
15 | 1839590adad5 |
hex | c3078128540 |
13402312443200 has 42 divisors (see below), whose sum is σ = 32978065059486. Its totient is φ = 5360924976640.
The previous prime is 13402312443181. The next prime is 13402312443271. The reversal of 13402312443200 is 234421320431.
It can be written as a sum of positive squares in 3 ways, for example, as 301734884416 + 13100577558784 = 549304^2 + 3619472^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4188221039 + ... + 4188224238.
Almost surely, 213402312443200 is an apocalyptic number.
13402312443200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13402312443200 is an abundant number, since it is smaller than the sum of its proper divisors (19575752616286).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402312443200 is an equidigital number, since it uses as much as digits as its factorization.
13402312443200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8376445299 (or 8376445284 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 13402312443200 its reverse (234421320431), we get a palindrome (13636733763631).
The spelling of 13402312443200 in words is "thirteen trillion, four hundred two billion, three hundred twelve million, four hundred forty-three thousand, two hundred".
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