Base | Representation |
---|---|
bin | 1100001100010011011000… |
… | …1011110111111110100110 |
3 | 1202110112221111002010200112 |
4 | 3003010312023313332212 |
5 | 3224113432003411400 |
6 | 44302222544013022 |
7 | 2552341560010556 |
oct | 303046613677646 |
9 | 52415844063615 |
10 | 13405502013350 |
11 | 42a9272451167 |
12 | 16060ab601172 |
13 | 763197163955 |
14 | 344b88c07166 |
15 | 183a940eb835 |
hex | c31362f7fa6 |
13405502013350 has 24 divisors (see below), whose sum is σ = 25234646207400. Its totient is φ = 5297595974720.
The previous prime is 13405502013331. The next prime is 13405502013361. The reversal of 13405502013350 is 5331020550431.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1615116575 + ... + 1615124874.
It is an arithmetic number, because the mean of its divisors is an integer number (1051443591975).
Almost surely, 213405502013350 is an apocalyptic number.
13405502013350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13405502013350 is a deficient number, since it is larger than the sum of its proper divisors (11829144194050).
13405502013350 is a wasteful number, since it uses less digits than its factorization.
13405502013350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3230241544 (or 3230241539 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 13405502013350 its reverse (5331020550431), we get a palindrome (18736522563781).
The spelling of 13405502013350 in words is "thirteen trillion, four hundred five billion, five hundred two million, thirteen thousand, three hundred fifty".
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