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13405502013350 = 252833230241449
BaseRepresentation
bin1100001100010011011000…
…1011110111111110100110
31202110112221111002010200112
43003010312023313332212
53224113432003411400
644302222544013022
72552341560010556
oct303046613677646
952415844063615
1013405502013350
1142a9272451167
1216060ab601172
13763197163955
14344b88c07166
15183a940eb835
hexc31362f7fa6

13405502013350 has 24 divisors (see below), whose sum is σ = 25234646207400. Its totient is φ = 5297595974720.

The previous prime is 13405502013331. The next prime is 13405502013361. The reversal of 13405502013350 is 5331020550431.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1615116575 + ... + 1615124874.

It is an arithmetic number, because the mean of its divisors is an integer number (1051443591975).

Almost surely, 213405502013350 is an apocalyptic number.

13405502013350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13405502013350 is a deficient number, since it is larger than the sum of its proper divisors (11829144194050).

13405502013350 is a wasteful number, since it uses less digits than its factorization.

13405502013350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3230241544 (or 3230241539 counting only the distinct ones).

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 13405502013350 its reverse (5331020550431), we get a palindrome (18736522563781).

The spelling of 13405502013350 in words is "thirteen trillion, four hundred five billion, five hundred two million, thirteen thousand, three hundred fifty".

Divisors: 1 2 5 10 25 50 83 166 415 830 2075 4150 3230241449 6460482898 16151207245 32302414490 80756036225 161512072450 268110040267 536220080534 1340550201335 2681100402670 6702751006675 13405502013350