1340802426040 has 128 divisors (see below), whose sum is σ = 3822871749120. Its totient is φ = 411061363200.

The previous prime is 1340802426023. The next prime is 1340802426043. The reversal of 1340802426040 is 406242080431.

It is a super-2 number, since 2×1340802426040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340802425987 and 1340802426005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340802426043) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3380362 + ... + 3756121.

It is an arithmetic number, because the mean of its divisors is an integer number (29866185540).

Almost surely, 2^{1340802426040} is an apocalyptic number.

1340802426040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1340802426040 is an abundant number, since it is smaller than the sum of its proper divisors (2482069323080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340802426040 is a wasteful number, since it uses less digits than its factorization.

1340802426040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7136573 (or 7136569 counting only the distinct ones).

The product of its (nonzero) digits is 36864, while the sum is 34.

The spelling of 1340802426040 in words is "one trillion, three hundred forty billion, eight hundred two million, four hundred twenty-six thousand, forty".