Base | Representation |
---|---|
bin | 1100001100100111111000… |
… | …1101010100101101100000 |
3 | 1202111002011000112002012221 |
4 | 3003021332031110231200 |
5 | 3224211214330220112 |
6 | 44304533015000424 |
7 | 2552625133233505 |
oct | 303117615245540 |
9 | 52432130462187 |
10 | 13411005320032 |
11 | 4300636973a01 |
12 | 1607186669114 |
13 | 763863364738 |
14 | 34514ba814ac |
15 | 183cb7320e07 |
hex | c327e354b60 |
13411005320032 has 24 divisors (see below), whose sum is σ = 26442148440456. Its totient is φ = 6695539049472.
The previous prime is 13411005320003. The next prime is 13411005320033. The reversal of 13411005320032 is 23002350011431.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 13411005319979 and 13411005320006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13411005320033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311340958 + ... + 311384029.
It is an arithmetic number, because the mean of its divisors is an integer number (1101756185019).
Almost surely, 213411005320032 is an apocalyptic number.
It is an amenable number.
13411005320032 is a deficient number, since it is larger than the sum of its proper divisors (13031143120424).
13411005320032 is an equidigital number, since it uses as much as digits as its factorization.
13411005320032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 622725670 (or 622725662 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 13411005320032 its reverse (23002350011431), we get a palindrome (36413355331463).
The spelling of 13411005320032 in words is "thirteen trillion, four hundred eleven billion, five million, three hundred twenty thousand, thirty-two".
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