Base | Representation |
---|---|
bin | 11000111110110101… |
… | …10101011000110000 |
3 | 1021121201002201100212 |
4 | 30133122311120300 |
5 | 204431434430000 |
6 | 10054510203252 |
7 | 653235242165 |
oct | 143732653060 |
9 | 37551081325 |
10 | 13412030000 |
11 | 5762817716 |
12 | 27237b3528 |
13 | 1359865b35 |
14 | 91338206c |
15 | 5376dec35 |
hex | 31f6b5630 |
13412030000 has 50 divisors (see below), whose sum is σ = 32471890044. Its totient is φ = 5364808000.
The previous prime is 13412029991. The next prime is 13412030053. The reversal of 13412030000 is 3021431.
It is a tau number, because it is divible by the number of its divisors (50).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 660602 + ... + 680601.
Almost surely, 213412030000 is an apocalyptic number.
13412030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13412030000 is an abundant number, since it is smaller than the sum of its proper divisors (19059860044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13412030000 is an equidigital number, since it uses as much as digits as its factorization.
13412030000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1341231 (or 1341210 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 13412030000 its reverse (3021431), we get a palindrome (13415051431).
The spelling of 13412030000 in words is "thirteen billion, four hundred twelve million, thirty thousand".
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