Base | Representation |
---|---|
bin | 111110011101110010… |
… | …0111011010011010000 |
3 | 110211020200200222020121 |
4 | 1330323210323103100 |
5 | 4144211220201000 |
6 | 141342533120024 |
7 | 12456126060265 |
oct | 1747344732320 |
9 | 424220628217 |
10 | 134143522000 |
11 | 51987580584 |
12 | 21bb8489014 |
13 | c85a4676b7 |
14 | 66c78dd26c |
15 | 37519d8b1a |
hex | 1f3b93b4d0 |
134143522000 has 80 divisors (see below), whose sum is σ = 324615397392. Its totient is φ = 53615001600.
The previous prime is 134143521907. The next prime is 134143522001. The reversal of 134143522000 is 225341431.
It can be written as a sum of positive squares in 8 ways, for example, as 3058974864 + 131084547136 = 55308^2 + 362056^2 .
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134143522001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2568144 + ... + 2619856.
Almost surely, 2134143522000 is an apocalyptic number.
134143522000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134143522000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (162307698696).
134143522000 is an abundant number, since it is smaller than the sum of its proper divisors (190471875392).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134143522000 is a wasteful number, since it uses less digits than its factorization.
134143522000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53033 (or 53017 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 134143522000 its reverse (225341431), we get a palindrome (134368863431).
The spelling of 134143522000 in words is "one hundred thirty-four billion, one hundred forty-three million, five hundred twenty-two thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •