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134143522000 = 2453129751713
BaseRepresentation
bin111110011101110010…
…0111011010011010000
3110211020200200222020121
41330323210323103100
54144211220201000
6141342533120024
712456126060265
oct1747344732320
9424220628217
10134143522000
1151987580584
1221bb8489014
13c85a4676b7
1466c78dd26c
1537519d8b1a
hex1f3b93b4d0

134143522000 has 80 divisors (see below), whose sum is σ = 324615397392. Its totient is φ = 53615001600.

The previous prime is 134143521907. The next prime is 134143522001. The reversal of 134143522000 is 225341431.

It can be written as a sum of positive squares in 8 ways, for example, as 3058974864 + 131084547136 = 55308^2 + 362056^2 .

It is a tau number, because it is divible by the number of its divisors (80).

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134143522001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2568144 + ... + 2619856.

Almost surely, 2134143522000 is an apocalyptic number.

134143522000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134143522000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (162307698696).

134143522000 is an abundant number, since it is smaller than the sum of its proper divisors (190471875392).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134143522000 is a wasteful number, since it uses less digits than its factorization.

134143522000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53033 (or 53017 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 134143522000 its reverse (225341431), we get a palindrome (134368863431).

The spelling of 134143522000 in words is "one hundred thirty-four billion, one hundred forty-three million, five hundred twenty-two thousand".

Divisors: 1 2 4 5 8 10 16 20 25 40 50 80 100 125 200 250 400 500 1000 1297 2000 2594 5188 6485 10376 12970 20752 25940 32425 51713 51880 64850 103426 103760 129700 162125 206852 258565 259400 324250 413704 517130 518800 648500 827408 1034260 1292825 1297000 2068520 2585650 2594000 4137040 5171300 6464125 10342600 12928250 20685200 25856500 51713000 67071761 103426000 134143522 268287044 335358805 536574088 670717610 1073148176 1341435220 1676794025 2682870440 3353588050 5365740880 6707176100 8383970125 13414352200 16767940250 26828704400 33535880500 67071761000 134143522000