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1342104479 is a prime number
BaseRepresentation
bin100111111111110…
…1110001110011111
310110112101222020022
41033333232032133
510222034320404
6341101542355
745154462022
oct11777561637
93415358208
101342104479
11629645a61
123155749bb
1318508a681
14ca3611b9
157cc5a8be
hex4ffee39f

1342104479 has 2 divisors, whose sum is σ = 1342104480. Its totient is φ = 1342104478.

The previous prime is 1342104443. The next prime is 1342104481. The reversal of 1342104479 is 9744012431.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (9744012431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1342104479 is a prime.

It is a super-2 number, since 2×13421044792 = 3602488865103722882, which contains 22 as substring.

Together with 1342104481, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342104419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671052239 + 671052240.

It is an arithmetic number, because the mean of its divisors is an integer number (671052240).

Almost surely, 21342104479 is an apocalyptic number.

1342104479 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342104479 is an equidigital number, since it uses as much as digits as its factorization.

1342104479 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The square root of 1342104479 is about 36634.7441508740. The cubic root of 1342104479 is about 1103.0506170627.

The spelling of 1342104479 in words is "one billion, three hundred forty-two million, one hundred four thousand, four hundred seventy-nine".