Base | Representation |
---|---|
bin | 11000111111111100… |
… | …10100001100000000 |
3 | 1021122100121021012202 |
4 | 30133332110030000 |
5 | 204441330044300 |
6 | 10055441412332 |
7 | 653410301324 |
oct | 143776241400 |
9 | 37570537182 |
10 | 13421331200 |
11 | 5767a9a862 |
12 | 272693a0a8 |
13 | 135b7715c4 |
14 | 9146c3984 |
15 | 53842aad5 |
hex | 31ff94300 |
13421331200 has 54 divisors (see below), whose sum is σ = 33219907644. Its totient is φ = 5368529920.
The previous prime is 13421331193. The next prime is 13421331221. The reversal of 13421331200 is 213312431.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1042142 + ... + 1054941.
Almost surely, 213421331200 is an apocalyptic number.
13421331200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13421331200 is an abundant number, since it is smaller than the sum of its proper divisors (19798576444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13421331200 is an equidigital number, since it uses as much as digits as its factorization.
13421331200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2097109 (or 2097090 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13421331200 its reverse (213312431), we get a palindrome (13634643631).
The spelling of 13421331200 in words is "thirteen billion, four hundred twenty-one million, three hundred thirty-one thousand, two hundred".
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