Base | Representation |
---|---|
bin | 1100001101011101101000… |
… | …1110100001100001111101 |
3 | 1202112110101120201000122021 |
4 | 3003113122032201201331 |
5 | 3224430242103243240 |
6 | 44315320444320141 |
7 | 2553645525313000 |
oct | 303273216414175 |
9 | 52473346630567 |
10 | 13425434040445 |
11 | 4306770574129 |
12 | 1609b32843051 |
13 | 76502272c61b |
14 | 345b1a077537 |
15 | 18435dddc54a |
hex | c35da3a187d |
13425434040445 has 64 divisors (see below), whose sum is σ = 18923973120000. Its totient is φ = 9139402456128.
The previous prime is 13425434040437. The next prime is 13425434040509. The reversal of 13425434040445 is 54404043452431.
It is not a de Polignac number, because 13425434040445 - 23 = 13425434040437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 256875726 + ... + 256927984.
It is an arithmetic number, because the mean of its divisors is an integer number (295687080000).
Almost surely, 213425434040445 is an apocalyptic number.
It is an amenable number.
13425434040445 is a deficient number, since it is larger than the sum of its proper divisors (5498539079555).
13425434040445 is an equidigital number, since it uses as much as digits as its factorization.
13425434040445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53367 (or 53353 counting only the distinct ones).
The product of its (nonzero) digits is 1843200, while the sum is 43.
Adding to 13425434040445 its reverse (54404043452431), we get a palindrome (67829477492876).
The spelling of 13425434040445 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty-four million, forty thousand, four hundred forty-five".
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