134265053655231 has 4 divisors (see below), whose sum is σ = 179020071540312. Its totient is φ = 89510035770152.

The previous prime is 134265053655217. The next prime is 134265053655259. The reversal of 134265053655231 is 132556350562431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134265053655231 - 2⁵ = 134265053655199 is a prime.

It is a super-3 number, since 3×134265053655231³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134265053455231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22377508942536 + ... + 22377508942541.

It is an arithmetic number, because the mean of its divisors is an integer number (44755017885078).

Almost surely, 2^{134265053655231} is an apocalyptic number.

134265053655231 is a deficient number, since it is larger than the sum of its proper divisors (44755017885081).

134265053655231 is an equidigital number, since it uses as much as digits as its factorization.

134265053655231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44755017885080.

The product of its (nonzero) digits is 9720000, while the sum is 51.

The spelling of 134265053655231 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, fifty-three million, six hundred fifty-five thousand, two hundred thirty-one".