1343130341340 has 48 divisors (see below), whose sum is σ = 3781774846080. Its totient is φ = 356167149120.

The previous prime is 1343130341249. The next prime is 1343130341351. The reversal of 1343130341340 is 431430313431.

It is a super-3 number, since 3×1343130341340³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 1343130341298 and 1343130341307.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62518606 + ... + 62540085.

It is an arithmetic number, because the mean of its divisors is an integer number (78786975960).

Almost surely, 2^{1343130341340} is an apocalyptic number.

1343130341340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1343130341340 is an abundant number, since it is smaller than the sum of its proper divisors (2438644504740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1343130341340 is a wasteful number, since it uses less digits than its factorization.

1343130341340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125058882 (or 125058880 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 1343130341340 its reverse (431430313431), we get a palindrome (1774560654771).

The spelling of 1343130341340 in words is "one trillion, three hundred forty-three billion, one hundred thirty million, three hundred forty-one thousand, three hundred forty".