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134331011544 = 23319037294013
BaseRepresentation
bin111110100011011000…
…0001001000111011000
3110211201202111102112210
41331012300021013120
54200102214332134
6141413311435120
712463563521112
oct1750660110730
9424652442483
10134331011544
1151a73399214
122204b225aa0
13c88a261562
1467047863b2
1537631c12e9
hex1f46c091d8

134331011544 has 32 divisors (see below), whose sum is σ = 335846311920. Its totient is φ = 44774499456.

The previous prime is 134331011527. The next prime is 134331011567. The reversal of 134331011544 is 445110133431.

It is a super-2 number, since 2×1343310115442 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 309882 + ... + 603894.

Almost surely, 2134331011544 is an apocalyptic number.

It is an amenable number.

134331011544 is an abundant number, since it is smaller than the sum of its proper divisors (201515300376).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134331011544 is a wasteful number, since it uses less digits than its factorization.

134331011544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 313059 (or 313055 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 134331011544 its reverse (445110133431), we get a palindrome (579441144975).

The spelling of 134331011544 in words is "one hundred thirty-four billion, three hundred thirty-one million, eleven thousand, five hundred forty-four".

Divisors: 1 2 3 4 6 8 12 24 19037 38074 57111 76148 114222 152296 228444 294013 456888 588026 882039 1176052 1764078 2352104 3528156 7056312 5597125481 11194250962 16791376443 22388501924 33582752886 44777003848 67165505772 134331011544