1343414543440 has 20 divisors (see below), whose sum is σ = 3123438813684. Its totient is φ = 537365817344.

The previous prime is 1343414543437. The next prime is 1343414543459. The reversal of 1343414543440 is 443454143431.

It can be written as a sum of positive squares in 2 ways, for example, as 432848199744 + 910566343696 = 657912^2 + 954236^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a super-2 number, since 2×1343414543440² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (40).

It is a junction number, because it is equal to n+sod(n) for n = 1343414543393 and 1343414543402.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8396340817 + ... + 8396340976.

Almost surely, 2^{1343414543440} is an apocalyptic number.

1343414543440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1343414543440 is an abundant number, since it is smaller than the sum of its proper divisors (1780024270244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1343414543440 is a wasteful number, since it uses less digits than its factorization.

1343414543440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16792681806 (or 16792681800 counting only the distinct ones).

The product of its (nonzero) digits is 552960, while the sum is 40.

Adding to 1343414543440 its reverse (443454143431), we get a palindrome (1786868686871).

The spelling of 1343414543440 in words is "one trillion, three hundred forty-three billion, four hundred fourteen million, five hundred forty-three thousand, four hundred forty".