134401000000 has 98 divisors (see below), whose sum is σ = 333375693674. Its totient is φ = 53760000000.

The previous prime is 134400999959. The next prime is 134401000003. The reversal of 134401000000 is 104431.

It can be written as a sum of positive squares in 7 ways, for example, as 134372098624 + 28901376 = 366568^2 + 5376^2 .

It is not an unprimeable number, because it can be changed into a prime (134401000003) by changing a digit.

It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 932800 + ... + 1067200.

Almost surely, 2^134401000000 is an apocalyptic number.

134401000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134401000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166687846837).

134401000000 is an abundant number, since it is smaller than the sum of its proper divisors (198974693674).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134401000000 is an frugal number, since it uses more digits than its factorization.

134401000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134443 (or 134408 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 134401000000 its reverse (104431), we get a palindrome (134401104431).

The spelling of 134401000000 in words is "one hundred thirty-four billion, four hundred one million", and thus it is an aban number.