13440112035 has 64 divisors (see below), whose sum is σ = 25190618112. Its totient is φ = 5990939136.

The previous prime is 13440112009. The next prime is 13440112073. The reversal of 13440112035 is 53021104431.

It is a happy number.

13440112035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13440112035 - 2⁵ = 13440112003 is a prime.

It is a super-3 number, since 3×13440112035³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13440111996 and 13440112014.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3054457 + ... + 3058853.

It is an arithmetic number, because the mean of its divisors is an integer number (393603408).

Almost surely, 2^13440112035 is an apocalyptic number.

13440112035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13440112035 is a deficient number, since it is larger than the sum of its proper divisors (11750506077).

13440112035 is a wasteful number, since it uses less digits than its factorization.

13440112035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5132.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 13440112035 its reverse (53021104431), we get a palindrome (66461216466).

The spelling of 13440112035 in words is "thirteen billion, four hundred forty million, one hundred twelve thousand, thirty-five".