134404381 has 2 divisors, whose sum is σ = 134404382. Its totient is φ = 134404380.

The previous prime is 134404379. The next prime is 134404409. The reversal of 134404381 is 183404431.

It is an a-pointer prime, because the next prime (134404409) can be obtained adding 134404381 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133772356 + 632025 = 11566^2 + 795^2 .

It is a cyclic number.

It is not a de Polignac number, because 134404381 - 2¹ = 134404379 is a prime.

It is a super-2 number, since 2×134404381² = 36129075263986322, which contains 22 as substring.

Together with 134404379, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134404181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67202190 + 67202191.

It is an arithmetic number, because the mean of its divisors is an integer number (67202191).

Almost surely, 2^134404381 is an apocalyptic number.

It is an amenable number.

134404381 is a deficient number, since it is larger than the sum of its proper divisors (1).

134404381 is an equidigital number, since it uses as much as digits as its factorization.

134404381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

The square root of 134404381 is about 11593.2903439878. The cubic root of 134404381 is about 512.2372316263.

Subtracting 134404381 from its reverse (183404431), we obtain a triangular number (49000050 = T₉₈₉₉).

The spelling of 134404381 in words is "one hundred thirty-four million, four hundred four thousand, three hundred eighty-one".