13441020233140 has 24 divisors (see below), whose sum is σ = 28260190947240. Its totient is φ = 5369922672768.

The previous prime is 13441020233099. The next prime is 13441020233167. The reversal of 13441020233140 is 4133202014431.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 588881272996 + 12852138960144 = 767386^2 + 3584988^2 .

It is a super-2 number, since 2×13441020233140² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13441020233099 and 13441020233108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 405321787 + ... + 405354946.

It is an arithmetic number, because the mean of its divisors is an integer number (1177507956135).

Almost surely, 2^{13441020233140} is an apocalyptic number.

13441020233140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13441020233140 is an abundant number, since it is smaller than the sum of its proper divisors (14819170714100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13441020233140 is a wasteful number, since it uses less digits than its factorization.

13441020233140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 810677571 (or 810677569 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 13441020233140 its reverse (4133202014431), we get a palindrome (17574222247571).

The spelling of 13441020233140 in words is "thirteen trillion, four hundred forty-one billion, twenty million, two hundred thirty-three thousand, one hundred forty".