Base | Representation |
---|---|
bin | 1100001110100000101110… |
… | …0001100111111111111000 |
3 | 1202121011212111222100222112 |
4 | 3003220023201213333320 |
5 | 3230224131344003230 |
6 | 44331455340111452 |
7 | 2555154000043433 |
oct | 303501341477770 |
9 | 52534774870875 |
10 | 13443441000440 |
11 | 4313370a7a750 |
12 | 1611519235588 |
13 | 766932228b39 |
14 | 34694779681a |
15 | 184a64bbcd95 |
hex | c3a0b867ff8 |
13443441000440 has 128 divisors (see below), whose sum is σ = 33399736473600. Its totient is φ = 4828955281920.
The previous prime is 13443441000433. The next prime is 13443441000461. The reversal of 13443441000440 is 4400014434431.
It is a super-2 number, since 2×134434410004402 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13443441000397 and 13443441000406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 316570649 + ... + 316613111.
It is an arithmetic number, because the mean of its divisors is an integer number (260935441200).
Almost surely, 213443441000440 is an apocalyptic number.
13443441000440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13443441000440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16699868236800).
13443441000440 is an abundant number, since it is smaller than the sum of its proper divisors (19956295473160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13443441000440 is a wasteful number, since it uses less digits than its factorization.
13443441000440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51237 (or 51233 counting only the distinct ones).
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 13443441000440 its reverse (4400014434431), we get a palindrome (17843455434871).
The spelling of 13443441000440 in words is "thirteen trillion, four hundred forty-three billion, four hundred forty-one million, four hundred forty", and thus it is an aban number.
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