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134444034252000 = 253453111011392687
BaseRepresentation
bin11110100100011010110000…
…111001110101110011100000
3122122000201112220111010120000
4132210122300321311303200
5120110212340232031000
61153534423043020000
740214155333451214
oct3644326071656340
9578021486433500
10134444034252000
11399244384284a0
12130b41a306a600
135a030307c6365
14252b1a997a944
1510822e7bc3000
hex7a46b0e75ce0

134444034252000 has 1920 divisors, whose sum is σ = 547758639267840. Its totient is φ = 32025715200000.

The previous prime is 134444034251977. The next prime is 134444034252001. The reversal of 134444034252000 is 252430444431.

134444034252000 is a `hidden beast` number, since 1 + 3 + 4 + 4 + 4 + 403 + 42 + 5 + 200 + 0 = 666.

134444034252000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134444034252001) by changing a digit.

It is a polite number, since it can be written in 319 ways as a sum of consecutive naturals, for example, 50034994657 + ... + 50034997343.

It is an arithmetic number, because the mean of its divisors is an integer number (285290957952).

Almost surely, 2134444034252000 is an apocalyptic number.

134444034252000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134444034252000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (273879319633920).

134444034252000 is an abundant number, since it is smaller than the sum of its proper divisors (413314605015840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134444034252000 is a wasteful number, since it uses less digits than its factorization.

134444034252000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2975 (or 2948 counting only the distinct ones).

The product of its (nonzero) digits is 184320, while the sum is 36.

Adding to 134444034252000 its reverse (252430444431), we get a palindrome (134696464696431).

The spelling of 134444034252000 in words is "one hundred thirty-four trillion, four hundred forty-four billion, thirty-four million, two hundred fifty-two thousand".