Base | Representation |
---|---|
bin | 1100010000101101111010… |
… | …0111001110100101001100 |
3 | 1202201210200220202210201120 |
4 | 3010023132213032211030 |
5 | 3231334242100401030 |
6 | 44401124302240540 |
7 | 2560665140655063 |
oct | 304133647164514 |
9 | 52653626683646 |
10 | 13481342200140 |
11 | 4328450239a91 |
12 | 1618936286150 |
13 | 76a392520619 |
14 | 34870130b1da |
15 | 185a322c8010 |
hex | c42de9ce94c |
13481342200140 has 48 divisors (see below), whose sum is σ = 39968214525792. Its totient is φ = 3383552551936.
The previous prime is 13481342200129. The next prime is 13481342200181. The reversal of 13481342200140 is 4100224318431.
13481342200140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6608500059 + ... + 6608502098.
It is an arithmetic number, because the mean of its divisors is an integer number (832671135954).
Almost surely, 213481342200140 is an apocalyptic number.
13481342200140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13481342200140 is an abundant number, since it is smaller than the sum of its proper divisors (26486872325652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13481342200140 is a wasteful number, since it uses less digits than its factorization.
13481342200140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13217002186 (or 13217002184 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 13481342200140 its reverse (4100224318431), we get a palindrome (17581566518571).
The spelling of 13481342200140 in words is "thirteen trillion, four hundred eighty-one billion, three hundred forty-two million, two hundred thousand, one hundred forty".
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