Base | Representation |
---|---|
bin | 101000001111000… |
… | …1111000111110101 |
3 | 10111002110100212212 |
4 | 1100132033013311 |
5 | 10231111303131 |
6 | 341545223205 |
7 | 45312455633 |
oct | 12036170765 |
9 | 3432410785 |
10 | 1350103541 |
11 | 633109856 |
12 | 318191b05 |
13 | 18692b547 |
14 | cb444353 |
15 | 7d7daa2b |
hex | 5078f1f5 |
1350103541 has 2 divisors, whose sum is σ = 1350103542. Its totient is φ = 1350103540.
The previous prime is 1350103511. The next prime is 1350103543. The reversal of 1350103541 is 1453010531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1132659025 + 217444516 = 33655^2 + 14746^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350103541 - 210 = 1350102517 is a prime.
Together with 1350103543, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350103543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675051770 + 675051771.
It is an arithmetic number, because the mean of its divisors is an integer number (675051771).
Almost surely, 21350103541 is an apocalyptic number.
It is an amenable number.
1350103541 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350103541 is an equidigital number, since it uses as much as digits as its factorization.
1350103541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 900, while the sum is 23.
The square root of 1350103541 is about 36743.7551292733. The cubic root of 1350103541 is about 1105.2377042998.
The spelling of 1350103541 in words is "one billion, three hundred fifty million, one hundred three thousand, five hundred forty-one".
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