Base | Representation |
---|---|
bin | 11110101100111101111010… |
… | …111110110111100111000000 |
3 | 122201002220000012102112000121 |
4 | 132230331322332313213000 |
5 | 120144324043232320000 |
6 | 1155104344432430024 |
7 | 40304464305105346 |
oct | 3654757276674700 |
9 | 581086005375017 |
10 | 135031540120000 |
11 | 3a030611150767 |
12 | 1318a0256a8314 |
13 | 5a4655bb0cb44 |
14 | 254b7c0737996 |
15 | 1092730c15b1a |
hex | 7acf7afb79c0 |
135031540120000 has 140 divisors (see below), whose sum is σ = 335516326701336. Its totient is φ = 53902602880000.
The previous prime is 135031540119997. The next prime is 135031540120003. The reversal of 135031540120000 is 21045130531.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (135031540119997) and next prime (135031540120003).
It is a super-2 number, since 2×1350315401200002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135031540120003) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 16202334 + ... + 23077666.
Almost surely, 2135031540120000 is an apocalyptic number.
135031540120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135031540120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167758163350668).
135031540120000 is an abundant number, since it is smaller than the sum of its proper divisors (200484786581336).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135031540120000 is an frugal number, since it uses more digits than its factorization.
135031540120000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6875856 (or 6875831 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 135031540120000 its reverse (21045130531), we get a palindrome (135052585250531).
The spelling of 135031540120000 in words is "one hundred thirty-five trillion, thirty-one billion, five hundred forty million, one hundred twenty thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •