Base | Representation |
---|---|
bin | 1100010011101000100001… |
… | …1010000010101010000000 |
3 | 1202220121000000011121221222 |
4 | 3010322020122002222000 |
5 | 3233144334442313100 |
6 | 44440131115534212 |
7 | 2564420405041313 |
oct | 304721032025200 |
9 | 52817000147858 |
10 | 13531435510400 |
11 | 4347716644455 |
12 | 162659645a368 |
13 | 772016700c02 |
14 | 34acd41aa97a |
15 | 186eb4e50485 |
hex | c4e88682a80 |
13531435510400 has 96 divisors (see below), whose sum is σ = 34138084754880. Its totient is φ = 5297412992000.
The previous prime is 13531435510399. The next prime is 13531435510429. The reversal of 13531435510400 is 401553413531.
It is a super-2 number, since 2×135314355104002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44834426 + ... + 45135225.
It is an arithmetic number, because the mean of its divisors is an integer number (355605049530).
Almost surely, 213531435510400 is an apocalyptic number.
13531435510400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13531435510400 is an abundant number, since it is smaller than the sum of its proper divisors (20606649244480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13531435510400 is an equidigital number, since it uses as much as digits as its factorization.
13531435510400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89969722 (or 89969705 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 13531435510400 its reverse (401553413531), we get a palindrome (13932988923931).
The spelling of 13531435510400 in words is "thirteen trillion, five hundred thirty-one billion, four hundred thirty-five million, five hundred ten thousand, four hundred".
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