Base | Representation |
---|---|
bin | 1100010011101111001011… |
… | …0110101011011011000001 |
3 | 1202220202121110122100002121 |
4 | 3010323302312223123001 |
5 | 3233212014134333210 |
6 | 44441024233444241 |
7 | 2564512561626253 |
oct | 304736266533301 |
9 | 52822543570077 |
10 | 13533221402305 |
11 | 4348452742480 |
12 | 16269b4570681 |
13 | 77223c6c1597 |
14 | 34b02344dcd3 |
15 | 18706bb1d6da |
hex | c4ef2dab6c1 |
13533221402305 has 64 divisors (see below), whose sum is σ = 18563563929600. Its totient is φ = 9375223601920.
The previous prime is 13533221402303. The next prime is 13533221402329. The reversal of 13533221402305 is 50320412233531.
It is not a de Polignac number, because 13533221402305 - 21 = 13533221402303 is a prime.
It is a super-2 number, since 2×135332214023052 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13533221402303) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 408607536 + ... + 408640654.
It is an arithmetic number, because the mean of its divisors is an integer number (290055686400).
Almost surely, 213533221402305 is an apocalyptic number.
It is an amenable number.
13533221402305 is a deficient number, since it is larger than the sum of its proper divisors (5030342527295).
13533221402305 is a wasteful number, since it uses less digits than its factorization.
13533221402305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34494.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 13533221402305 its reverse (50320412233531), we get a palindrome (63853633635836).
The spelling of 13533221402305 in words is "thirteen trillion, five hundred thirty-three billion, two hundred twenty-one million, four hundred two thousand, three hundred five".
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