Base | Representation |
---|---|
bin | 1100010011110000010110… |
… | …0011000100111110111001 |
3 | 1202220210102022210100002112 |
4 | 3010330011203010332321 |
5 | 3233213134431444400 |
6 | 44441115315542105 |
7 | 2564523420501266 |
oct | 304740543047671 |
9 | 52823368710075 |
10 | 13533535031225 |
11 | 43485a3785530 |
12 | 1626a815ba935 |
13 | 77228c681921 |
14 | 34b052d7026d |
15 | 187089420835 |
hex | c4f058c4fb9 |
13533535031225 has 72 divisors (see below), whose sum is σ = 19142079516000. Its totient is φ = 9412505132800.
The previous prime is 13533535031207. The next prime is 13533535031251. The reversal of 13533535031225 is 52213053533531.
13533535031225 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13533535031225 - 220 = 13533533982649 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 920703926 + ... + 920718624.
It is an arithmetic number, because the mean of its divisors is an integer number (265862215500).
Almost surely, 213533535031225 is an apocalyptic number.
It is an amenable number.
13533535031225 is a deficient number, since it is larger than the sum of its proper divisors (5608544484775).
13533535031225 is a wasteful number, since it uses less digits than its factorization.
13533535031225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21095 (or 21067 counting only the distinct ones).
The product of its (nonzero) digits is 607500, while the sum is 41.
Adding to 13533535031225 its reverse (52213053533531), we get a palindrome (65746588564756).
The spelling of 13533535031225 in words is "thirteen trillion, five hundred thirty-three billion, five hundred thirty-five million, thirty-one thousand, two hundred twenty-five".
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