Base | Representation |
---|---|
bin | 1100010100001001010010… |
… | …1100000110001001000111 |
3 | 1202221102201000101102102120 |
4 | 3011002110230012021013 |
5 | 3233320343231120310 |
6 | 44444144012341023 |
7 | 2565151362541665 |
oct | 305022454061107 |
9 | 52842630342376 |
10 | 13540231504455 |
11 | 435041a766a27 |
12 | 1628230174773 |
13 | 772ab8b23716 |
14 | 34b4ca479c35 |
15 | 18732c280b70 |
hex | c5094b06247 |
13540231504455 has 16 divisors (see below), whose sum is σ = 22606299555840. Its totient is φ = 6907480419488.
The previous prime is 13540231504381. The next prime is 13540231504487. The reversal of 13540231504455 is 55440513204531.
It is a cyclic number.
It is not a de Polignac number, because 13540231504455 - 211 = 13540231502407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19623523575 + ... + 19623524264.
It is an arithmetic number, because the mean of its divisors is an integer number (1412893722240).
Almost surely, 213540231504455 is an apocalyptic number.
13540231504455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13540231504455 is a deficient number, since it is larger than the sum of its proper divisors (9066068051385).
13540231504455 is a wasteful number, since it uses less digits than its factorization.
13540231504455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39247047870.
The product of its (nonzero) digits is 720000, while the sum is 42.
Adding to 13540231504455 its reverse (55440513204531), we get a palindrome (68980744708986).
The spelling of 13540231504455 in words is "thirteen trillion, five hundred forty billion, two hundred thirty-one million, five hundred four thousand, four hundred fifty-five".
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