Base | Representation |
---|---|
bin | 11110110010110101001001… |
… | …110100010110011101110101 |
3 | 122202112101222010210002021201 |
4 | 132302311021310112131311 |
5 | 120222424214201030140 |
6 | 1200013420202412501 |
7 | 40345546506242614 |
oct | 3662651164263565 |
9 | 582471863702251 |
10 | 135434442205045 |
11 | 3a176473946555 |
12 | 13234128801131 |
13 | 5a7554a76bc69 |
14 | 25630c20d587b |
15 | 109ce622b149a |
hex | 7b2d49d16775 |
135434442205045 has 64 divisors (see below), whose sum is σ = 174821644800000. Its totient is φ = 100475056281600.
The previous prime is 135434442205039. The next prime is 135434442205063. The reversal of 135434442205045 is 540502244434531.
It is not a de Polignac number, because 135434442205045 - 221 = 135434440107893 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135434442204986 and 135434442205004.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 932549446 + ... + 932694664.
It is an arithmetic number, because the mean of its divisors is an integer number (2731588200000).
Almost surely, 2135434442205045 is an apocalyptic number.
It is an amenable number.
135434442205045 is a deficient number, since it is larger than the sum of its proper divisors (39387202594955).
135434442205045 is a wasteful number, since it uses less digits than its factorization.
135434442205045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146690.
The product of its (nonzero) digits is 4608000, while the sum is 46.
Adding to 135434442205045 its reverse (540502244434531), we get a palindrome (675936686639576).
The spelling of 135434442205045 in words is "one hundred thirty-five trillion, four hundred thirty-four billion, four hundred forty-two million, two hundred five thousand, forty-five".
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